Question 725: Thermodynamics & KTG

Question

A monoatomic ideal gas is heated at constant pressure. The percentage of total heat used in changing the internal energy is

Accepted Answer

For a monoatomic ideal gas being heated at constant pressure, we need to determine the percentage of the total heat that is used in changing the internal energy.
Given for a monoatomic gas:
$ \gamma = \frac{C_p}{C_v} = \frac{5}{3} $
We know the change in heat, $\Delta Q$, is described by:
$ \Delta Q = nC_p \Delta T $
And the change in internal energy, $\Delta U$, is given by:
$ \Delta U = nC_v \Delta T $
To find the ratio of the change in internal energy to the change in heat supplied, we use:
$ \frac{\Delta U}{\Delta Q} = \frac{nC_v \Delta T}{nC_p \Delta T} = \frac{C_v}{C_p} = \frac{3}{5} $
Therefore, the percentage of total heat used in changing the internal energy is:
$ \frac{3}{5} 	imes 100 = 60\% $

Answer

$30 \%$

Answer

$40 \%$

Answer

$50 \%$

Answer

$60 \%$

Thermodynamics & KTG

A monoatomic ideal gas is heated at constant pressure. The percentage of total heat used in changing the internal energy is

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