Question 472: Thermodynamics & KTG

Question

Two kg of a monoatomic gas is at a pressure of 4 $$ 	imes $$ 104 N/m2. The density of the gas is 8 kg/m3. What is the order of energy of the gas due to its thermal motion ?

Accepted Answer

Thermal energy of N molecule
=  N$$\left( {{3 \over 2}kT} ight)$$
=  $${N \over {{N_A}}}{3 \over 2}$$RT
=  $${3 \over 2}$$(nRT)
=  $${3 \over 2}$$PV
=  $${3 \over 2}$$P$$\left( {{m \over 8}} ight)$$
=  $${3 \over 2}$$ $$ 	imes $$ 4 $$ 	imes $$ 10
4
$$ 	imes $$ $${2 \over 8}$$
=  1.5 $$ 	imes $$ 10
4
order will 10
4

Answer

104 J

Answer

103 J

Answer

105 J

Answer

106 J

Thermodynamics & KTG

Two kg of a monoatomic gas is at a pressure of 4 $ \times $ 104 N/m2. The density of the gas is 8 kg/m3. What is the order of energy of the gas due to its thermal motion ?

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