Question 394: Thermodynamics & KTG

Question

The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is :

Accepted Answer

No. of moles of O
2
:
n
1
= $${{16} \over {32}}$$ = 0.5 mole
No. of moles of N
2
:
n
2
= $${{28} \over {28}}$$ = 1 mole
No. of moles of CO
2
:
n
3
= $${{44} \over {44}}$$ = 1 mole
Total no. of moles in container : n = n
1
+ n
2
+ n
3
$$ 	herefore $$ n = 0.5 + 1 + 1 = $${5 \over 2}$$ moles
Now; PV = nRT
$$ \Rightarrow $$ P = $${{nRT} \over V}$$
$$ \Rightarrow $$ P = $${5 \over 2}{{RT} \over V}$$

Answer

$${{3RT} \over V}$$

Answer

$${{4RT} \over V}$$

Answer

$${{88RT} \over V}$$

Answer

$${5 \over 2}{{RT} \over V}$$

Thermodynamics & KTG

The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is :

Choose the correct answer: