Question 236: Thermodynamics & KTG

Question

The translational degrees of freedom $$\left(f_t\right)$$ and rotational degrees of freedom $$\left(f_r\right)$$ of $$\mathrm{CH}_4$$ molecule are:

Accepted Answer

For non-linear polyatomic molecules, both 
translational and rotational degree of freedom have 
same value and is equal to 3.

Answer

$$f_t=2$$ and $$f_r=2$$

Answer

$$f_t=3$$ and $$f_r=3$$

Answer

$$f_t=3$$ and 4$f_r=2$$

Answer

$$f_t=2$$ and $$f_r=3$$

Thermodynamics & KTG