Question 914: Thermodynamics & KTG

Question

The temperature of a black body is increased by $$50 \%$$, then the percentage increase in the rate of radiation by the body is approximated

Accepted Answer

Rate of radiation $$\mathrm{R} \propto \mathrm{T}^4$$
$$\begin{aligned}
& 	herefore \frac{R_2}{R_1}=\left(\frac{T_2}{T_1}ight)^4=(1.5)^4 \approx 5 \
& 	herefore R_2=5 R_1 \
& R_2-R_1=4 R_1 \
& \frac{\mathrm{R}_2-\mathrm{R}_1}{\mathrm{R}_1}=4 \
\end{aligned}$$
$$	ext { Percentage increase }=\left(\frac{R_2-R_1}{R_1}ight) 	imes 100=400 \%$$

Answer

50%

Answer

100%

Answer

400%

Answer

150%

Thermodynamics & KTG

The temperature of a black body is increased by $50 \%$, then the percentage increase in the rate of radiation by the body is approximated

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