Question 944: Thermodynamics & KTG

Question

A conducting rod of length $$1 \mathrm{~m}$$ has area of cross-section $$10^{-3} \mathrm{~m}^2$$. One end is immersed in baiting water $$\left(100^{\circ} \mathrm{C}ight)$$ and the other end in Ice $$\left(0^{\circ} \mathrm{C}ight)$$. If coefficient of thermal conductivity of $$\mathrm{rod}$$ is $$96 \mathrm{~cal} / \mathrm{sm}^{\circ} \mathrm{C}$$ and latent heat for ice is $$8 	imes 10^{-4} \mathrm{cal} / \mathrm{kg}$$ then the amount of ice which will melt in one minute is

Accepted Answer

$$\begin{aligned} & \mathrm{d}=1 \mathrm{~m}, \mathrm{~A}=10^{-3} \mathrm{~m}^2, \mathrm{~K}=96 \mathrm{cal} / \mathrm{s} \mathrm{m}{ }^{\circ} \mathrm{C}, \mathrm{L}=8 	imes 10^4 \mathrm{cal} / \mathrm{kg} \ & \mathrm{t}=1 \mathrm{~min}=60 \mathrm{~s}, 	heta_1=0^{\circ} \mathrm{C}, 	heta_2=100^{\circ} \mathrm{C} \ & \mathrm{Q}=\frac{\mathrm{KA} \Delta 	heta \mathrm{t}}{\mathrm{d}}=\mathrm{mL}\end{aligned}$$
$$\begin{aligned} 	herefore \mathrm{m} & =\frac{\mathrm{KA} \Delta 	heta \mathrm{t}}{\mathrm{L}}=\frac{96 	imes 10^{-3} 	imes 100 	imes 60}{80 	imes 10^4} \ & =7.2 	imes 10^{-3} \mathrm{~kg}\end{aligned}$$

Answer

$$5.4 	imes 10^{-3} \mathrm{~kg}$$

Answer

$$7.2 	imes 10^{-3} \mathrm{~kg}$$

Answer

$$1.8 	imes 10^{-3} \mathrm{~kg}$$

Answer

$$3.6 	imes 0^{-3} \mathrm{~kg}$$

Thermodynamics & KTG

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