Question 757: Thermodynamics & KTG

Question

For a gas, $\frac{\mathrm{R}}{\mathrm{C}_{\mathrm{v}}}=0.4$ where R is the universal gas constant and ' $\mathrm{C}_{\mathrm{V}}$ ' is molar specific heat at constant volume. The gas is made up of molecules which are

Accepted Answer

Given: $\frac{R}{C_v} = 0.4$
To determine the type of gas molecules, we start with the given ratio:
Finding $C_v$:
$    C_v = \frac{R}{0.4} = \frac{5R}{2}    $
Calculate $C_p$:
$    C_p = C_v + R = \frac{5R}{2} + R = \frac{7R}{2}    $
Determine $\gamma$ (the heat capacity ratio):
$    \gamma = \frac{C_p}{C_v} = \frac{\frac{7R}{2}}{\frac{5R}{2}} = \frac{7}{5}    $
The value of $\gamma = \frac{7}{5}$ is characteristic of gases made up of rigid diatomic molecules. Hence, the gas consists of rigid diatomic molecules.

Answer

rigid diatomic.

Answer

monoatomic.

Answer

non-rigid diatomic.

Answer

polyatomic.

Thermodynamics & KTG

For a gas, \frac{\mathrm{R}}{\mathrm{C}_{\mathrm{v}}}=0.4 where R is the universal gas constant and ' \mathrm{C}_{\mathrm{V}} ' is molar specific heat at constant volume. The gas is made up of molecules which are

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