Question 499: Thermodynamics & KTG

Question

CP and Cv are specific heats at constant pressure and constant volume respectively. It is observed that CP – Cv = a for hydrogen gas CP – Cv = b for nitrogen gas The correct relation between a and b is

Accepted Answer

As we know, for 1 g mole of a gas,
C
p
Ã¢ÂÂ C
v
= R where C
p
and C
v
are molar
specific heat capacities.
So, when n gram moles are given,
C
p
Ã¢ÂÂ C
v
= $${R \over n}$$
For hydrogen (n = 2), C
p
Ã¢ÂÂ C
v
= $${R \over 2}$$ = $$a$$
For nitrogen (n = 28), C
p
Ã¢ÂÂ C
v
= $${R \over 28}$$ = $$b$$
$$ 	herefore $$ $${a \over b} = 14$$
$$ \Rightarrow $$  $$a$$ = 14 $$b$$

Answer

a = 28 b

Answer

a = 1/14 b

Answer

a = b

Answer

a = 14 b

Thermodynamics & KTG

CP and Cv are specific heats at constant pressure and constant volume respectively. It is observed that CP – Cv = a for hydrogen gas CP – Cv = b for nitrogen gas The correct relation between a and b is

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