Question 364: Properties of Matter

Question

The two ends of a rod of length L and a uniform cross-sectional area A are Kept at two temperatures T1 and T2 (T1 > T2). The rate of heat transfer, $${{dQ} \over {dt}}$$ through the rod in a steady state is given by :

Accepted Answer

Similar to I = V/R
$${{dQ} \over {dt}} = {{kA} \over L}\left( {{T_1} - {T_2}} \right)$$
k = conductivity of the rod.

Answer

$${{dQ} \over {dt}} = {{k\left( {{T_1} - {T_2}} \right)} \over {LA}}$$

Answer

$${{dQ} \over {dt}} = kLA({T_1} - {T_2})$$

Answer

$${{dQ} \over {dt}} = {{kA\left( {{T_1} - {T_2}} \right)} \over L}$$

Answer

$${{dQ} \over {dt}} = {{kL\left( {{T_1} - {T_2}} \right)} \over A}$$

Properties of Matter

The two ends of a rod of length L and a uniform cross-sectional area A are Kept at two temperatures T1 and T2 (T1 > T2). The rate of heat transfer, ${{dQ} \over {dt}}$ through the rod in a steady state is given by :

Choose the correct answer: