Question 300: Properties of Matter

Question

An ideal fluid is flowing in a non-uniform cross-sectional tube $$X Y$$ (as shown in the figure) from end $$X$$ to end $$Y$$. If $$K_1$$ and $$K_2$$ are the kinetic energy per unit volume of the fluid at $$X$$ and $$Y$$ respectively, then the correct option is :

Accepted Answer

According to Bernoulli's principle,
Kinetic energy per unit volume + Potential energy per unit volume + Pressure $$=$$ Constant
$$\frac{1}{2} ho V^2+ho g h+P=	ext { constant }$$
Apply Bernoulli's principle at point $$X$$ and $$Y$$,
$$\begin{aligned}
& P+K_1+ho g(0)=P+K_2+ho g(\mathrm{~h}) \
& K_1=K_2+ho g h \
& K_1>K_2
\end{aligned}$$

Answer

$$K_1=K_2$$

Answer

$$2 K_1=K_2$$

Answer

$$K_1>K_2$$

Answer

$$K_1 < K_2$$

Properties of Matter

An ideal fluid is flowing in a non-uniform cross-sectional tube $X Y (as shown in the figure) from end X to end Y. If K_1 and K_2 are the kinetic energy per unit volume of the fluid at X and Y$ respectively, then the correct option is :

Choose the correct answer: