Question 94: Gravitation

Question

A planet takes 200 days to complete one revolution around the Sun. If the distance of the planet from Sun is reduced to one fourth of the original distance, how many days will it take to complete one revolution :

Accepted Answer

$$\begin{aligned}
& \mathrm{T}^2 \propto \mathrm{r}^3 \
& \frac{\mathrm{T}_1^2}{\mathrm{r}_1^3}=\frac{\mathrm{T}_2^2}{\mathrm{r}_2^3} \
& \frac{(200)^2}{\mathrm{r}^3}=\frac{\mathrm{T}_2^2}{\left(\frac{\mathrm{r}}{4}ight)^3} \
& \frac{200 	imes 200}{4 	imes 4 	imes 4}=\mathrm{T}_2^2 \
& \mathrm{~T}_2=\frac{200}{4 	imes 2} \
& \mathrm{~T}_2=25 	ext { days }
\end{aligned}$$

Answer

20

Answer

50

Answer

100

Answer

25

Gravitation

A planet takes 200 days to complete one revolution around the Sun. If the distance of the planet from Sun is reduced to one fourth of the original distance, how many days will it take to complete one revolution :

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