Question 429: Gravitation

Question

A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be

Accepted Answer

Since the man is in gravity free space, force on man + stone system is zero.
Therefore centre of mass of the system remains at rest. Let the man goes x m above when the stone reaches the floor, then
M
man
ÃÂ x = M
stone
ÃÂ 10
$$x = {{0.5} \over {50}} 	imes 10$$
x = 0.1 m
Therefore final height of man above floor = 10 + x = 10 + 0.1 = 10.1 m

Answer

9.9 m

Answer

10.1 m

Answer

10 m

Answer

20 m

Gravitation

A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be

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