Question 242: Gravitation

Question

The escape velocity for a body projected vertically upwards from the surface of earth is $$11$$ $$km/s.$$ If the body is projected at an angle of $${45^ \circ }$$  with the vertical, the escape velocity will be

Accepted Answer

We know, Escape velocity, $${v_e} = \sqrt {2gR} $$
So the escape velocity is independent of the angle at which the body is projected, hence it will remain same as 11 km/s.

Answer

$$11\sqrt 2 \,\,km/s$$

Answer

$$22$$ $$km/s$$

Answer

$$11$$ $$km/s$$

Answer

$${{11} \over {\sqrt 2 }}km/s$$

Gravitation

The escape velocity for a body projected vertically upwards from the surface of earth is $11 km/s. If the body is projected at an angle of {45^ \circ }$ with the vertical, the escape velocity will be

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