Question 396: Gravitation

Question

The escape velocity from the Earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is :

Accepted Answer

$${v_e} = \sqrt {{{2GM} \over R}}  = \sqrt {{{2G} \over R} 	imes {4 \over 3}\pi {R^3}ho } $$
$$ = \sqrt {{{8\pi Gho } \over 3}{R^2}} $$
$$ \Rightarrow {v_e} \propto R$$
$$ \Rightarrow {{{v_e}} \over \upsilon } = {{4R} \over R} \Rightarrow {v_e} = 4v$$

Answer

4$$\upsilon $$

Answer

$$\upsilon $$

Answer

2$$\upsilon $$

Answer

3$$\upsilon $$

Gravitation

The escape velocity from the Earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is :

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