Question 142: Gravitation

Question

The percentage decrease in the weight of a rocket, when taken to a height of $$32 \mathrm{~km}$$ above the surface of earth will, be :
$$($$ Radius of earth $$=6400 \mathrm{~km})$$

Accepted Answer

$$\because$$ $$g = {{GM} \over {{r^2}}}$$
$$ \Rightarrow {{\Delta g} \over g} = 2{{\Delta r} \over r}$$
$$ \Rightarrow {{\Delta g} \over g} 	imes 100 = 2 	imes {{32} \over {6400}} 	imes 100\%  = 1\% $$
$$\Rightarrow$$ % decrease in weight = 1%

Answer

1%

Answer

3%

Answer

4%

Answer

0.5%

Gravitation

The percentage decrease in the weight of a rocket, when taken to a height of $32 \mathrm{~km} above the surface of earth will, be : ( Radius of earth =6400 \mathrm{~km})

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