Question 370: Gravitation

Question

The escape velocity of a body from any planet, whose mass is six times the mass of earth and radius is twice the radius of earth will (v$_e$ = escape velocity of a body from the earth's surface)

Accepted Answer

The escape velocity of body from earth's surface is
$$v_e=\sqrt{\frac{2 G M}{R}}$$
where, $G$ is universal gravitational constant, $M^{	ext {is }}$ mass of earth and $R$ is the radius of earth.
For the planet, $M_1=6 M$ and $R_1=2 R$
$	herefore$ The escape velocity from the planet will be
$$v_p=\sqrt{\frac{2 G(6 M)}{(2 R)}}=\sqrt{3} v_e$$

Answer

$2 \sqrt{2} v_e$

Answer

$\frac{3}{2} v_e$

Answer

$2 v_e$

Answer

$\sqrt{3} v_e$

Gravitation

The escape velocity of a body from any planet, whose mass is six times the mass of earth and radius is twice the radius of earth will (v_e = escape velocity of a body from the earth's surface)

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