Question 7: Centre of Mass and Rotational Motion

Question

The velocity - mass graph of body with constant linear momentum is represented by the graph:

Accepted Answer

Let m_C=12Ã¢ÂÂu and m_O=16Ã¢ÂÂu, and let r=0.12Ã¢ÂÂnm be the CÃ¢ÂÂO separation.  Choosing the CÃ¢ÂÂatom as the origin, the centre of mass lies at
$$d_C=\frac{m_O}{m_C+m_O}\;r.$$
Plugging in:
$$d_C=\frac{16}{12+16}	imes0.12\ {m nm} =\frac{16}{28}	imes0.12\approx0.0686\ {m nm}\approx0.07\ {m nm}.$$
Answer: 0.07Ã¢ÂÂnm (Option D).

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Centre of Mass and Rotational Motion

The velocity - mass graph of body with constant linear momentum is represented by the graph:

Choose the correct answer: