Question 212: Centre of Mass and Rotational Motion

Question

Four point masses, each of mass m, are fixed at the corners of a square of side $$l$$. The square is
rotating with angular frequency $$\omega $$, about an axis passing through one of the corners of the square
and parallel to its diagonal, as shown in the figure. The angular momentum of the square about this
axis is :

Accepted Answer

I = $$m\left( {{{{l^2}} \over 2}} ight) 	imes 2 + m 	imes {\left( {\sqrt 2 l} ight)^2}$$
= $$3m{l^2}$$
$$ 	herefore $$ L = I$$\omega $$ = $$3m{l^2}\omega $$

Answer

3m$$l$$2$$\omega $$

Answer

4m$$l$$2$$\omega $$

Answer

m$$l$$2$$\omega $$

Answer

2m$$l$$2$$\omega $$

Centre of Mass and Rotational Motion

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