Question 101: Centre of Mass and Rotational Motion

Question

Two billiard balls of mass 0.05 kg each moving in opposite directions with 10 ms$$-$$1 collide and rebound with the same speed. If the time duration of contact is t = 0.005 s, then what is the force exerted on the ball due to each other?

Accepted Answer

Change in momentum of one ball
= 2 $$	imes$$ (0.05)(10) kg m/s
= 1 kg m/s
$$ \Rightarrow {F_{avg}} = {1 \over {\Delta t}} = {1 \over {0.005}}$$ N
= 200 N

Answer

100 N

Answer

200 N

Answer

300 N

Answer

400 N

Centre of Mass and Rotational Motion

Two billiard balls of mass 0.05 kg each moving in opposite directions with 10 ms$-$1 collide and rebound with the same speed. If the time duration of contact is t = 0.005 s, then what is the force exerted on the ball due to each other?

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