Question 478: Centre of Mass and Rotational Motion

Question

A same torque is applied to a disc and a ring of equal mass and radii then

Accepted Answer

Moment of inertia of disc $\mathrm{t}_{\mathrm{d}}=\frac{\mathrm{MR}^2}{2}$
Moment of inertia of ring $\mathrm{I}_{\mathrm{r}}=\mathrm{MR}^2$
$$ 	herefore \quad I_r>I_d $$
Angular acceleration $\alpha=\frac{	au}{1}$
As torque is same, $\alpha \propto \frac{1}{1}$
$$ \because \quad \alpha_d>\alpha_r $$
$	herefore \quad$ Disc will rotate with greater angular frequency

Answer

the ring will rotate with greater angular frequency.

Answer

both will rotate with same angular frequency.

Answer

the disc will rotate with greater angular frequency.

Answer

both will rotate with same angular velocity.

Centre of Mass and Rotational Motion

A same torque is applied to a disc and a ring of equal mass and radii then

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