Question 694: Centre of Mass and Rotational Motion

Question

A point P consider at contact point of a wheel on ground which rolls on ground without slipping then value of displacement of point P when wheel completes half of rotation (if radius of wheel is 1 m)

Accepted Answer

In half rotation point P has moved horizontally.
$${{\pi d} \over 2} = \pi r = \pi  	imes 1m = \pi \,m$$   $$\left[ \because {radius = 1m} ight]$$
In the same time, it has moved vertically a distance which is equal to its diameter = 2 m.
$$ 	herefore $$ Displacement of P = $$\sqrt {{\pi ^2} + {2^2}}  = \sqrt {{\pi ^2} + 4} $$ m

Answer

2 m

Answer

$$\sqrt {{\pi ^2} + 4} m$$

Answer

$$\pi \,m$$

Answer

$$\sqrt {{\pi ^2} + 2} \,m$$

Centre of Mass and Rotational Motion

A point P consider at contact point of a wheel on ground which rolls on ground without slipping then value of displacement of point P when wheel completes half of rotation (if radius of wheel is 1 m)

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