Question 238: Centre of Mass and Rotational Motion

Question

A uniform sphere of mass 500 g rolls without
slipping on a plane horizontal surface with its
centre moving at a speed of 5.00 cm/s. Its
kinetic energy is :

Accepted Answer

K.E = $${1 \over 2}m{V^2} + {1 \over 2}{I_{cm}}{\omega ^2}$$
= $${1 \over 2}m{V^2} + {1 \over 2} 	imes {2 \over 5}m{R^2} 	imes {{{V^2}} \over {{R^2}}}$$
= $${1 \over 2}m{V^2} + {1 \over 5}m{V^2}$$
= $${7 \over {10}}m{V^2}$$
= $${7 \over {10}} 	imes 0.5 	imes 25 	imes {10^{ - 4}}$$
= $${{35} \over 4} 	imes {10^{ - 4}}$$
= 8.75 ÃÂ 10
Ã¢ÂÂ4
J

Answer

8.75 × 10–3 J

Answer

1.13 × 10–3 J

Answer

8.75 × 10–4 J

Answer

6.25 × 10–4 J

Centre of Mass and Rotational Motion

A uniform sphere of mass 500 g rolls without slipping on a plane horizontal surface with its centre moving at a speed of 5.00 cm/s. Its kinetic energy is :

Choose the correct answer: