Question 632: Centre of Mass and Rotational Motion

Question

Two particles A and B are moving in uniform circular motion in concentric circles of radii rA and rB with speed vA and vB respecitively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be :

Accepted Answer

Since, the time period for both the particle in same
So, T
A
= T
B
= T
Angular velocity for A, ($${\omega _A}$$) = $${{2\pi } \over {{T_A}}}$$
Angular velocity for B, ($${\omega _B}$$) = $${{2\pi } \over {{T_B}}}$$
Now, the required ratio is
$${{{\omega _A}} \over {{\omega _B}}} = {{{T_B}} \over {{T_A}}} = {T \over T} = 1$$

Answer

vA : vB

Answer

1 : 1

Answer

rB : rA

Answer

rA : rB

Centre of Mass and Rotational Motion

Two particles A and B are moving in uniform circular motion in concentric circles of radii rA and rB with speed vA and vB respecitively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be :

Choose the correct answer: