Question 118: Centre of Mass and Rotational Motion

Question

A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is

Accepted Answer

$$\begin{aligned}
& 	au_{	ext {Net }}=0 \Rightarrow(400 \mathrm{~g} 	imes 30)=(250 \mathrm{~g} 	imes 10)(\mathrm{mg} 	imes 50) \
& \mathrm{m}=\frac{12000-2500}{50}=\frac{9500}{50} \
& \mathrm{M}=190 \mathrm{~g}
\end{aligned}$$

Answer

290 g

Answer

200 g

Answer

190 g

Answer

300 g

Centre of Mass and Rotational Motion

A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is

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