Question 349: Centre of Mass and Rotational Motion

Question

A particle of mass '$$m$$' collides with another stationary particle of mass '$$M$$'. A particle of mass '$$\mathrm{m}$$' stops just after collision. The coefficient of restitution is

Accepted Answer

Let $$\mathrm{v}$$ be the velocity of mass $$\mathrm{m}$$ and $$\mathrm{v}^{\prime}$$ be the velocity of mass $$\mathrm{M}$$ after collision. By law of conservation of momentum
$$\begin{aligned}
\mathrm{mv} & =\mathrm{Mv}^{\prime} \
	herefore \frac{\mathrm{v}^{\prime}}{\mathrm{v}}=\frac{\mathrm{m}}{\mathrm{M}} & \
	ext { Coefficient of restitutions } & =\frac{	ext { Relative velocity after collision }}{	ext { Re lative velocity before collision }} \
& =\frac{\mathrm{v}^{\prime}}{\mathrm{v}}
\end{aligned}$$

Answer

$$\frac{M}{m}$$

Answer

$$\frac{m+M}{M}$$

Answer

$$\frac{M-m}{M+m}$$

Answer

$$\frac{\mathrm{m}}{\mathrm{M}}$$

Centre of Mass and Rotational Motion

A particle of mass '$m' collides with another stationary particle of mass 'M'. A particle of mass '\mathrm{m}$' stops just after collision. The coefficient of restitution is

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