Question 555: Centre of Mass and Rotational Motion

Question

In $$\mathrm{P}^{	ext {th }}$$ second, a particle describes angular displacement of '$$\beta$$' rad. If it starts from rest, the angular acceleration is

Accepted Answer

The equation for the angular displacement of the particle that starts from rest is given as:
$$\beta=0+\frac{1}{2} \alpha(2 \mathrm{P}-1)$$
$$	herefore \quad$$ The angular acceleration of the particle is $$\alpha=\frac{2 \beta}{(2 \mathrm{P}-1)}$$

Answer

$$\frac{\beta}{P}$$

Answer

$$\frac{\beta}{(\mathrm{P}-1)}$$

Answer

$$\frac{2 \beta}{(2 \mathrm{P}-1)}$$

Answer

$$\frac{(2 \beta+1)}{(2 \mathrm{P}-1)}$$

Centre of Mass and Rotational Motion

In $\mathrm{P}^{\text {th }} second, a particle describes angular displacement of '\beta$' rad. If it starts from rest, the angular acceleration is

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