Question 121: Centre of Mass and Rotational Motion

Question

If the Kinetic energy of a moving body becomes four times its initial Kinetic energy, then the percentage change in its momentum will be :

Accepted Answer

K
2
= 4K
1
$${1 \over 2}$$mv$$_2^2$$ = 4$${1 \over 2}$$mv$$_1^2$$
v
2
= 2v
1
P = mv
P
2
= mv
2
= 2mv
1
P
1
= mv
1
% change = $${{\Delta P} \over {{P_1}}} 	imes 100 = {{2m{v_1} - m{v_1}} \over {m{v_1}}} 	imes 100 = 100\% $$

Answer

100%

Answer

200%

Answer

300%

Answer

400%

Centre of Mass and Rotational Motion

If the Kinetic energy of a moving body becomes four times its initial Kinetic energy, then the percentage change in its momentum will be :

Choose the correct answer: