Question 698: Centre of Mass and Rotational Motion

Question

As shown in the figure at point O a mass is performing vertical circular motion. The average velocity of the particle is increased, then at which point will the string break

Accepted Answer

When a sphere is rotating in a vertical circle, it exerts the maximum outward pull when it is at the lowest point B.
Therefore, tension at B is maximum = $${{m{v^2}} \over R}$$
So, the string breaks at point B.

Answer

A

Answer

B

Answer

C

Answer

D

Centre of Mass and Rotational Motion

As shown in the figure at point O a mass is performing vertical circular motion. The average velocity of the particle is increased, then at which point will the string break

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