Question 678: Centre of Mass and Rotational Motion

Question

A particle of mass m moves in the XY plane with a velocity v along the straight line AB. If the angular momentum of the particle with  respect to origin  O is LA when it is at A and LB when  it is at B, then

Accepted Answer

Angular momentum = Linear momentum ÃÂ
perpendicular distance between line of action of
liner momentum from origin
Let d be the perpendicular distance.
p
A
and p
B
be the linear momentum at A and B
Angular momentum L
A
= p
A
ÃÂ d
L
B
= p
B
ÃÂ d
So, linear momentum will be equal, i.e., L
A
= L
B
.here,
p
A
and p
B
are equal as have equal velocity.
L
A
= L
B

Answer

LA = LB

Answer

the relationship between  LA and LB depends upon  the slope of the line AB

Answer

LA < LB

Answer

LA > LB.

Centre of Mass and Rotational Motion

A particle of mass m moves in the XY plane with a velocity v along the straight line AB. If the angular momentum of the particle with respect to origin O is LA when it is at A and LB when it is at B, then

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