Question 314: Centre of Mass and Rotational Motion

Question

A thin circular disk is in the xy plane as shown in the figure. The ratio of its moment of inertia about z and z' axes will be :

Accepted Answer

As we know,
moment of inertia about z axis
$${{m I}_z} = {{m{R^2}} \over 2}$$
and moment of inertia about z'
$${m I}_z^1 = {3 \over 2}m{R^2}$$
$$	herefore\,\,\,\,$$ $${{{{m I}_z}} \over {{m I}{'_z}}}$$ = $${{{{m{R^2}} \over 2}} \over {{3 \over 2}m{R^2}}}$$ = $${1 \over 3}$$

Answer

1 : 3

Answer

1 : 4

Answer

1 : 5

Answer

1 : 2

Centre of Mass and Rotational Motion

A thin circular disk is in the xy plane as shown in the figure. The ratio of its moment of inertia about z and z' axes will be :

Choose the correct answer: