Question 98: Work, Energy and Power & Circular Motion

Question

A particle of mass 500 gm is moving in a straight line with velocity v = b x5/2. The work done by the net force during its displacement from x = 0 to x = 4 m is : (Take b = 0.25 m$$-$$3/2 s$$-$$1).

Accepted Answer

$${W_{total}} = \Delta K$$
$$ = {1 \over 2}\left( {{1 \over 2}} ight)\left[ {{{\{ b{{(4)}^{5/2}}\} }^2} - 0} ight]$$
$$ = {{{b^2}} \over 4} 	imes {4^5}$$
$$ \Rightarrow {W_{total}} = 16\,J$$

Answer

2 J

Answer

4 J

Answer

8 J

Answer

16 J

Work, Energy and Power & Circular Motion

A particle of mass 500 gm is moving in a straight line with velocity v = b x5/2. The work done by the net force during its displacement from x = 0 to x = 4 m is : (Take b = 0.25 m$-3/2 s-$1).

Choose the correct answer: