Question 52: Work, Energy and Power & Circular Motion

Question

A body of $$m \mathrm{~kg}$$ slides from rest along the curve of vertical circle from point $$A$$ to $$B$$ in friction less path. The velocity of the body at $$B$$ is:

(given, $$R=14 \mathrm{~m}, g=10 \mathrm{~m} / \mathrm{s}^2$$ and $$\sqrt{2}=1.4$$)

Accepted Answer

From energy conservation $$ightarrow$$
$$\begin{aligned}
& m g(R+R \sin 45)=\frac{1}{2} m v^2 \
& \Rightarrow 10\left(1+\frac{1}{\sqrt{2}}ight) 	imes 14=\frac{1}{2} v^2 \
& \Rightarrow 10\left(1+\frac{\sqrt{2}}{2}ight) 	imes 28=v^2 \
& \Rightarrow 10(1+0.7) 	imes 28=v^2 \
& \Rightarrow v=21.81
\end{aligned}$$

Answer

10.6 m/s

Answer

19.8 m/s

Answer

16.7 m/s

Answer

21.9 m/s

Work, Energy and Power & Circular Motion

A body of $m \mathrm{~kg} slides from rest along the curve of vertical circle from point A to B in friction less path. The velocity of the body at B is: (given, R=14 \mathrm{~m}, g=10 \mathrm{~m} / \mathrm{s}^2 and \sqrt{2}=1.4$)

Choose the correct answer: