Question 249: Work, Energy and Power & Circular Motion

Question

A body of mass '$$\mathrm{m}$$' attached at the end of a string is just completing the loop in a vertical circle. The apparent weight of the body at the lowest point in its path is ( $$\mathrm{g}$$ = gravitational acceleration)

Accepted Answer

The tension at the lowest point is $$\mathrm{T}=\frac{\mathrm{mv}^2}{\mathrm{r}}+\mathrm{mg}$$
To complete the vertical circle, the minimum velocity should be $$\mathrm{v}=\sqrt{5 \mathrm{gr}}$$
$$\begin{aligned}
	herefore \quad \mathrm{T} & =\frac{\mathrm{m}(\sqrt{5 \mathrm{gr}})^2}{\mathrm{r}}+\mathrm{mg} \
\mathrm{R} & =5 \mathrm{mg}+\mathrm{mg} \
	herefore \quad \mathrm{T} & =6 \mathrm{mg}
\end{aligned}$$

Answer

zero

Answer

$$\mathrm{mg}$$

Answer

$$3 \mathrm{~mg}$$

Answer

$$6 \mathrm{~mg}$$

Work, Energy and Power & Circular Motion

A body of mass '$\mathrm{m}' attached at the end of a string is just completing the loop in a vertical circle. The apparent weight of the body at the lowest point in its path is ( \mathrm{g}$ = gravitational acceleration)

Choose the correct answer: