Question 278: Work, Energy and Power & Circular Motion

Question

A force of F = (5y + 20)$$\widehat j$$ N acts on a particle. The work done by this force when the particle is moved from y = 0 m to y = 10 m is ___________ J.

Accepted Answer

F = (5y + 20)$$\widehat j$$
$$W  = \int {Fdy = \int\limits_0^{10} {(5y + 20)dy} } $$
$$ = \left( {{{5{y^2}} \over 2} + 20y} ight)_0^{10}$$
$$ = {5 \over 2} 	imes 100 + 20 	imes 10$$
$$ = 250 + 200 = 450$$ J

Work, Energy and Power & Circular Motion

A force of F = (5y + 20)$\widehat j$ N acts on a particle. The work done by this force when the particle is moved from y = 0 m to y = 10 m is ___________ J.

Choose the correct answer: