Question 53: Motion in 2D & Vectors

Question

The initial speed of a projectile fired from ground is $$\mathrm{u}$$. At the highest point during its motion, the speed of projectile is $$\frac{\sqrt{3}}{2} u$$. The time of flight of the projectile is :

Accepted Answer

$u \cos 	heta=\frac{\sqrt{3}}{2} u$
$$ \Rightarrow $$ $\cos 	heta=\frac{\sqrt{3}}{2}$
$$ \Rightarrow $$ $	heta=30^{\circ}$
Time of flight $=\frac{2 u \sin 	heta}{g}=\left(\frac{u}{g}ight)$

Answer

$$\frac{u}{g}$$

Answer

$$\frac{2u}{g}$$

Answer

$$\frac{u}{2g}$$

Answer

$$\frac{\sqrt3u}{g}$$

Motion in 2D & Vectors

The initial speed of a projectile fired from ground is $\mathrm{u}. At the highest point during its motion, the speed of projectile is \frac{\sqrt{3}}{2} u$. The time of flight of the projectile is :

Choose the correct answer: