Question 159: Motion in 2D & Vectors

Question

A ball is projected from point A with velocity $$20 \mathrm{~m} \mathrm{~s}^{-1}$$ at an angle $$60^{\circ}$$ to the horizontal direction. At the highest point $$\mathrm{B}$$ of the path (as shown in figure), the velocity $$\mathrm{v} \mathrm{m} \mathrm{s}^{-1}$$ of the ball will be:

Accepted Answer

At the top most point of its trajectory particle will have only horizontal component of velocity
$$\begin{aligned}
& \mathrm{V} 	ext { at top }=v \cos 	heta \
& =20 	imes \frac{1}{2} \
& =10 \mathrm{~m} / \mathrm{s}
\end{aligned}$$

Answer

20

Answer

$$10 \sqrt{3}$$

Answer

Zero

Answer

10

Motion in 2D & Vectors

A ball is projected from point A with velocity $20 \mathrm{~m} \mathrm{~s}^{-1} at an angle 60^{\circ} to the horizontal direction. At the highest point \mathrm{B} of the path (as shown in figure), the velocity \mathrm{v} \mathrm{m} \mathrm{s}^{-1}$ of the ball will be:

Choose the correct answer: