Question 134: Units , Dimensions and Error Analysis

Question

The dimension of mutual inductance is :

Accepted Answer

$$\because$$ $$U = {1 \over 2}M{i^2}$$
$$ \Rightarrow [M] = {{[U]} \over {[{i^2}]}} = {{M{L^2}{T^{ - 2}}} \over {{A^2}}}$$
$$ = [M{L^2}{T^{ - 2}}{A^{ - 2}}]$$

Answer

$$[M{L^2}{T^{ - 2}}{A^{ - 1}}]$$

Answer

$$[M{L^2}{T^{ - 3}}{A^{ - 1}}]$$

Answer

$$[M{L^2}{T^{ - 2}}{A^{ - 2}}]$$

Answer

$$[M{L^2}{T^{ - 3}}{A^{ - 2}}]$$

Units , Dimensions and Error Analysis

The dimension of mutual inductance is :

Choose the correct answer: