Question 892: Electrostats & Capacitance

Question

In case of dimensions of electric field and electric dipole moment the power of mass is reswpectively,

Accepted Answer

To determine the dimensions of the electric field and the electric dipole moment concerning the power of mass, let's analyze each one:
Electric Field:
The expression for the electric field $ E $ is given by:
$ E = \frac{F}{q} $
Where $ F $ is the force and $ q $ is the electric charge.
The dimensions of force $ F $ are:
$ [F] = [	ext{MLT}^{-2}] $
The dimensions of charge $ q $ are:
$ [q] = [AT] $
Therefore, the dimensions of the electric field $ E $ are:
$ [E] = \frac{[	ext{MLT}^{-2}]}{[AT]} = [	ext{MLT}^{-3} 	ext{A}^{-1}] $
This shows that the power of mass in the dimensions of the electric field is $ 1 $.
Electric Dipole Moment:
The electric dipole moment $ m $ is defined as $ m = 1 	imes A $, where $ I $ is the current and $ A $ is the area.
The dimensions are given by:
$ [m] = [AL^2] = [M^0 L^2 T^0 A] $
This indicates that the power of mass in the dimensions of the electric dipole moment is $ 0 $.
In summary, for the electric field, the power of mass is $ 1 $, and for the electric dipole moment, it is $ 0 $.

Answer

1, 1

Answer

1, 0

Answer

0, 1

Answer

0, 0

Electrostats & Capacitance

In case of dimensions of electric field and electric dipole moment the power of mass is reswpectively,

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