Question 298: Electrostats & Capacitance

Question

The equivalent capacitance between $$A$$ and $$B$$ in the circuit given below, is :

Accepted Answer

Given circuit :
Simplified circuit.
The equivalent capacitance between C and D = 2 + 5 + 5 = 12 $$\mu $$F
Equivalent capacitance between E and B  = 4 + 2 = 6 $$\mu $$F
Now equivalent capacitance between A and B
$${1 \over {{C_{eq}}}}$$ = $${1 \over 6}$$ + $${1 \over 12}$$ + $${1 \over 6}$$ = $${5 \over 12}$$
$$ \Rightarrow $$$$\,\,\,\,$$ C
eq
= $${12 \over 5}$$ = 2.4 $$\mu $$F
Note
:
(1) When capacitors C
1
, C
2
, . . . .C
n
are in parallel then equivalent capacitance
C
eq
= C
1
+ C
2
+ . . . . + C
n
(2) When capacitor C
1
,  C
2
. . . . . . C
n
are in series the equivalent capacitance
$${1 \over {{C_{eq}}}}$$ = $${1 \over {{C_1}}}$$ + $${1 \over {{C_2}}}$$ + . . . . . + $${1 \over {{C_n}}}$$

Answer

$$2.4\,\mu F$$

Answer

$$4.9\,\mu F$$

Answer

$$3.6\,\mu F$$

Answer

$$5.4\,\mu F$$

Electrostats & Capacitance

The equivalent capacitance between $A and B$ in the circuit given below, is :

Choose the correct answer: