Question 314: Electrostats & Capacitance

Question

In the given circuit, charges $${Q_2}$$ on the $$2\mu F$$ capacitor changes as $$C$$ is varied from $$1\,\mu F$$ to $$3\mu F.$$ $${Q_2}$$ as a function of $$'C'$$ is given properly by: 
$$\left( {figures\,\,are\,\,drawn\,\,schematically\,\,and\,\,are\,\,not\,\,to\,\,scale} \right)$$

Accepted Answer

From figure, $${Q_2} = {2 \over {2 + 1}}Q = {2 \over 3}Q$$
$$Q = E\left( {{{C 	imes 3} \over {C + 3}}} ight)$$
$$	herefore$$ $${Q_2} = {2 \over 3}\left( {{{3CE} \over {C + 3}}} ight) = {{2CE} \over {C + 3}}$$
Therefore graph $$d$$ correctly dipicts.

Answer

Answer

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Electrostats & Capacitance

In the given circuit, charges ${Q_2} on the 2\mu F capacitor changes as C is varied from 1\,\mu F to 3\mu F. {Q_2} as a function of 'C' is given properly by: \left( {figures\,\,are\,\,drawn\,\,schematically\,\,and\,\,are\,\,not\,\,to\,\,scale} \right)

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