Question 384: Electrostats & Capacitance

Question

As shown in the figure, two parallel plate capacitors having equal plate area of $$200 \mathrm{~cm}^{2}$$ are joined in such a way that $$a 
eq b$$. The equivalent capacitance of the combination is $$x \in_{0} \mathrm{~F}$$. The value of $$x$$ is ____________.

Accepted Answer

$$
\begin{aligned}
& c=\frac{\varepsilon_0 A}{(d-c)} \\
& =\frac{\varepsilon_0 	imes 200 	imes 10^{-4}}{4 	imes 10^{-3}} \\
& 	herefore x=5
\end{aligned}
$$
The situation is equivalent to a conducting slab placed between the plates

Electrostats & Capacitance

As shown in the figure, two parallel plate capacitors having equal plate area of $200 \mathrm{~cm}^{2} are joined in such a way that a \neq b. The equivalent capacitance of the combination is x \in_{0} \mathrm{~F}. The value of x$ is ____________.

Choose the correct answer: