Question 887: Electrostats & Capacitance

Question

A spherical conducting shell of inner radius 'r$$_1$$' and outer radius 'r$$_2$$' has a charge 'Q'. A charge $$-$$q is placed at the centre of the shell. The surface charge density on the inner and outer surface of the shell will be

Accepted Answer

Due to charge $$-$$q at the centre of the shell, a charge q will be induced on the inner surface and $$-$$q on the outer surface. The charge on outer surface will become Q $$-$$ q. Hence, surface change densities will be $$\frac{q}{4 \pi r_1^2}$$ and $$\frac{\mathrm{Q}-\mathrm{q}}{4 \pi \mathrm{r}_2^2}$$

Answer

$$\frac{q}{4 \pi r_1^2}$$ and $$\frac{\mathrm{Q}-\mathrm{q}}{4 \pi \mathrm{r}_2^2}$$

Answer

$$\frac{q}{4 \pi r_1^2}$$ and $$\frac{Q}{4 \pi r_2^2}$$

Answer

$$\frac{-q}{4 \pi r_1^2}$$ and $$\frac{Q+q}{4 \pi r_2^2}$$

Answer

zero and $$\frac{\mathrm{Q}-\mathrm{q}}{4 \pi \mathrm{r}_2^2}$$

Electrostats & Capacitance

A spherical conducting shell of inner radius 'r$_1' and outer radius 'r_2' has a charge 'Q'. A charge -$q is placed at the centre of the shell. The surface charge density on the inner and outer surface of the shell will be

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