Question 824: Electrostats & Capacitance

Question

The electric potential at the centre of two concentric half rings of radii $R_1$ and $R_2$, having same linear charge density ' $\lambda$ ' is ($\varepsilon_0=$ permittivity of free space)

Accepted Answer

$$\begin{aligned}
& \mathrm{V}_1=\frac{1}{4 \pi \varepsilon_0} 	imes \frac{\lambda\left(\pi \mathrm{R}_1ight)}{\mathrm{R}_1} \
& \mathrm{~V}_2=\frac{1}{4 \pi \varepsilon_0} 	imes \frac{\lambda\left(\pi \mathrm{R}_2ight)}{\mathrm{R}_2} \
& \mathrm{~V}_{\mathrm{net}}=\mathrm{V}_1+\mathrm{V}_2=\frac{1}{4 \pi \varepsilon_0} 	imes \pi \lambda 	imes 2=\frac{\lambda}{2 \varepsilon_0}
\end{aligned}$$

Answer

$\frac{2 \lambda}{\varepsilon_0}$

Answer

$\frac{\lambda}{2 \varepsilon_0}$

Answer

$\frac{\lambda}{4 \varepsilon_0}$

Answer

$\frac{\lambda}{\varepsilon_0}$

Electrostats & Capacitance

The electric potential at the centre of two concentric half rings of radii R_1 and R_2, having same linear charge density ' \lambda ' is (\varepsilon_0= permittivity of free space)

Choose the correct answer: