Question 859: Electrostats & Capacitance

Question

Assume that an electric field $$\mathrm{E}=30 \mathrm{x}^2 \hat{\mathrm{i}}$$ exists in space. If '$$\mathrm{V}_0$$' is the potential at the origin and '$$V_A$$' is the potential at $$x=2 \mathrm{~m}$$, then the potential difference $$\left(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_0\right)$$ is

Accepted Answer

$$\begin{aligned}
& d V=\vec{E} \cdot d x \
& \int_\limits{V_0}^{V_A} d V=-\int_\limits0^2 30 x^2 d x \
& V_A-V_0=-\left[10 x^3ight]_0^2=-80 J
\end{aligned}$$

Answer

$$-80 \mathrm{~J}$$

Answer

$$-120 \mathrm{~J}$$

Answer

$$80 \mathrm{~J}$$

Answer

$$120 \mathrm{~J}$$

Electrostats & Capacitance

Assume that an electric field $\mathrm{E}=30 \mathrm{x}^2 \hat{\mathrm{i}} exists in space. If '\mathrm{V}_0' is the potential at the origin and 'V_A' is the potential at x=2 \mathrm{~m}, then the potential difference \left(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_0\right)$ is

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