Question 785: Electrostats & Capacitance

Question

A hollow cylinder has a charge of ' $q$ ' $C$ within it. If $\phi$ is the electric flux associated with the curved surface B, the flux linked with the plane surface A will be

Accepted Answer

As per Gauss' law the net flux through closed surface is,
$$ \phi_{\mathrm{A}}+\phi_{\mathrm{B}}+\phi_{\mathrm{C}}=\frac{\mathrm{q}}{\varepsilon_0} $$
Due to symmetry, the same flux passes through plane surfaces A and C , i.e., $\phi_{\mathrm{A}}=\phi_{\mathrm{C}}$
$$ \begin{aligned} 	herefore & 2 \phi_A+\phi=\frac{q}{\varepsilon_0}\,\,\,\,\,\,\,\,\,\,\, Ã¢ÂÂ¦. (Given: $\phi_{\mathrm{B}}=\phi$ )\ & \phi_A=\frac{1}{2}\left(\frac{q}{\varepsilon_0}-\phiight) \end{aligned} $$

Answer

$\frac{\phi}{3}$

Answer

$\frac{\mathrm{q}}{\varepsilon_0}-\phi$

Answer

$\frac{\mathrm{q}}{3 \varepsilon_0}$

Answer

$\quad \frac{1}{2}\left(\frac{\mathrm{q}}{\varepsilon_0}-\phi\right)$

Electrostats & Capacitance

A hollow cylinder has a charge of ' q ' C within it. If \phi is the electric flux associated with the curved surface B, the flux linked with the plane surface A will be

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