Question 58: Electrostats & Capacitance

Question

In the figure below, the capacitance of each capacitor is $$3 \mu \mathrm{F}$$. The effective capacitance between $$A$$ and $$B$$ is

Accepted Answer

From figure,
$$C_1=C_2=C_3=C_4=3 \mu \mathrm{F}
\quad$$ (given)
$$\because C_4$$ and $$C_3$$ are in parallel, i.e.
$$C_{	ext {eq }}=C_4+C_3=(3+3) \mu \mathrm{F}=6 \mu \mathrm{F}$$
Now arrangement of capacitors will be as follows
$$\because C_1$$ is in parallel with the series combination of $$C_2$$ and $$C_{	ext {eq }}^{\prime}$$.
$$	herefore C_{	ext {eq }}^{\prime \prime}$$ between $$A$$ and $$B$$
$$=\frac{\left(C_2 	imes C_{	ext {eq }}^{\prime}ight)}{C_2+C_{	ext {eq }}^{\prime}}+C_1 \Rightarrow\left(\frac{3 	imes 6}{3+6}ight)+3=5 \mu \mathrm{F}$$

Answer

$$\frac{3}{4} \mu \mathrm{F}$$

Answer

$$3 \mu \mathrm{F}$$

Answer

$$6 \mu \mathrm{F}$$

Answer

$$5 \mu \mathrm{F}$$

Electrostats & Capacitance

In the figure below, the capacitance of each capacitor is $3 \mu \mathrm{F}. The effective capacitance between A and B$ is

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