Question 658: Electrostats & Capacitance

Question

The electrostatic force between the metal plates
of an isolated parallel plate capacitor C having
a charge Q and area A, is

Accepted Answer

In an isolated capacitor Q is constant, so an
electrostatic force between metal plates is given as:
F = QE = Q $$ 	imes $$ $${\sigma  \over {2{\varepsilon _0}}}$$ = $${{{Q^2}} \over {2A{\varepsilon _0}}}$$ [$$ \because $$ $$\sigma  = {Q \over {A}}$$]
F is independent of the distance between plates.

Answer

Independent of the distance between the
plates

Answer

Linearly proportional to the distance
between the plates

Answer

Proportional to the square root of the
distance between the plates

Answer

Inversely proportional to the distance
between the plates

Electrostats & Capacitance

The electrostatic force between the metal plates of an isolated parallel plate capacitor C having a charge Q and area A, is

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